(2r+5)(3r^2-16r+t)=0

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Solution for (2r+5)(3r^2-16r+t)=0 equation:


Simplifying
(2r + 5)(3r2 + -16r + t) = 0

Reorder the terms:
(5 + 2r)(3r2 + -16r + t) = 0

Reorder the terms:
(5 + 2r)(-16r + 3r2 + t) = 0

Multiply (5 + 2r) * (-16r + 3r2 + t)
(5(-16r + 3r2 + t) + 2r * (-16r + 3r2 + t)) = 0
((-16r * 5 + 3r2 * 5 + t * 5) + 2r * (-16r + 3r2 + t)) = 0
((-80r + 15r2 + 5t) + 2r * (-16r + 3r2 + t)) = 0
(-80r + 15r2 + 5t + (-16r * 2r + 3r2 * 2r + t * 2r)) = 0

Reorder the terms:
(-80r + 15r2 + 5t + (2rt + -32r2 + 6r3)) = 0
(-80r + 15r2 + 5t + (2rt + -32r2 + 6r3)) = 0

Reorder the terms:
(-80r + 2rt + 15r2 + -32r2 + 6r3 + 5t) = 0

Combine like terms: 15r2 + -32r2 = -17r2
(-80r + 2rt + -17r2 + 6r3 + 5t) = 0

Solving
-80r + 2rt + -17r2 + 6r3 + 5t = 0

Solving for variable 'r'.

The solution to this equation could not be determined.

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